KO4YAW Read Bulletin

Message 29089 in TECH.WW

From: G8MNY
Date: Mon, 31 Aug 26 07:05:00 Z
Newsgroups: TECH.WW
Subject: An AF amplifier stage
Message-ID: <3768_GB7CIP>
Path: N2MH4|VE3KPG|GB7CIP

R:260831/0706Z 36368@N2MH4.#SENC.NC.USA.NOAM LinBPQ6.0.24
R:260831/0706Z 123@VE3KPG.#ECON.ON.CAN.NOAM BPQ6.0.25
R:260831/0705Z @:GB7CIP.#32.GBR.EURO #:3768 [Caterham Surrey GBR] $:3768_GB7CIP

From: G8MNY@GB7CIP.#32.GBR.EURO
To  : TECH@WW

By G8MNY                                (Updated Dec 04)
(8 Bit ASCII graphics use code page 437 or 850, Terminal Font)

This simple amplifier circuit is easy for calculations.


                    Rc                 / \






                    Re


BASE BIAS R = Hfe x (Rc+Re) Approx



GAIN = Rc/Re approx (Rc may be lower due to external load).
     With high transisitor current gain Hfe, then Ie approx = Ic, so the
     emitter NFB Re controls the collector current making the voltage gain just
     the voltage drop ratio of Rc/Re. Assuming no external loads. For high gain
     applications Re includes the internal emitter R of the transistor
     (typically a few ohms).


     This is the added components, including the apparent fraction of the bias
     Rb with load current in it.
     "//" means in parallel, many of the paralleled terms are insignificant.
     Technically the amount that (G-1)x Rb component that affects the output Z
     it will also depend the input source Z.
 
Input Z = XCin + ((Hfe x Re) // (Rb/(G+1)))
     This is the added components, including the apparent fraction of the bias
     Rb with input current in it.
     "//" means in parallel, many of the paralleled terms are insignificant.

LF Roll off

     6dB/Octave roll off when Xc equals the source + load Zs.

HF Response
     Intrinsically limited by the transistor's FT when the Hfe becomes 1, and
     component layout (inter capacitance) causing Miller HF N.F.B. effects
     between output & input.

HF Compensation
     HF loss can be compensated for by putting a suitable C across Re to give
     +3dB boost were Xc=Re, e.g. where the measure drop is -3dB. The 6dB/Octave
     lift after that should flatten the amp losses out. The input Z will be
     reduced at HF though. Not often used!

EXAMPLE


                  1K









So in the above example Collector should be around +6V
Gain about 9 times
Output Z about 900R + XCout
Input Z about 5K + XCin

LF response with input source Z of zero, and output load of 10K...





Why don't U send an interesting bul?

73 De John, G8MNY @ GB7CIP




← Return to Bulletin List